> 
> > I don't understand your assembler syntax, and gcc does not understand it as
> > well, at least when *I* code like you...
> > I only know the (modern) syntax
> >    "move.l d0, d1"
> > but not your
> >    "move%.l %/d0,%/d1"
> > What is the meaning of this ambigous '%'??
> 
> What version of gcc are you using? 
> 
> The "%." conditionally expands to ".", and the "%/" conditionally expands
> to "%", depending on the base assembler syntax.  Using them can get you
> most of the way to portability across AT&T, MOT and MIT syntaxes.
> 
I use gcc 2.7.2. It seems that gcc version after 2.6.0 (???) only like MIT syntax.

> 
> r~
> 
Ruben



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